我有一个三个纬度坐标,它们组成两条线段 A 到 B 到 C.我还发现了一个函数,可以以 -180 到 180 的方式返回线段 A-B 或 B-C 的北向.但是,我无法确定汽车何时从 A 到达 B,应该右转还是左转继续前往 C.
I have a three lat-lon coordinates that make up two line segment A to B to C. I also found a function that can return north-bearing of a line segment A-B or B-C in -180 to 180 manner. However, I'm having trouble to determine when a car reaches from A to B, should it turn right or left to continue to C.
之前的答案是错误的.现在这是正确的
Previous answer was wrong. now this is the correct
public Direction GetDirection(Point a, Point b, Point c)
{
double theta1 = GetAngle(a, b);
double theta2 = GetAngle(b, c);
double delta = NormalizeAngle(theta2 - theta1);
if ( delta == 0 )
return Direction.Straight;
else if ( delta == Math.PI )
return Direction.Backwards;
else if ( delta < Math.PI )
return Direction.Left;
else return Direction.Right;
}
private Double GetAngle(Point p1, Point p2)
{
Double angleFromXAxis = Math.Atan ((p2.Y - p1.Y ) / (p2.X - p1.X ) ); // where y = m * x + K
return p2.X - p1.X < 0 ? m + Math.PI : m ); // The will go to the correct Quadrant
}
private Double NormalizeAngle(Double angle)
{
return angle < 0 ? angle + 2 * Math.PI : angle; //This will make sure angle is [0..2PI]
}
这篇关于如何计算转弯方向的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!