在我看到的例子中,参数是通过以下方式通过引用传递的:
In the examples that I saw the arguments were passed by reference in the following way:
void AddOne(int &y)
在我拥有的代码中,我看到以下语法:
In the code that I have I see the following syntax:
void AddOne(int& y)
我想知道它是否相同,或者第二种情况与第一种情况有什么不同.
I wonder if it is the same or the second case is somehow different from the first one.
两者完全相同.完全没有区别.
Both are exactly the same. No difference at all.
重要的是&
应该在type 和变量 名称之间.空格无所谓.
All that matters is that &
should be between the type and the variable name. Spaces don't matter.
所以
void AddOne(int& y);
void AddOne(int &y);
void AddOne(int & y)
void AddOne(int & y);
void AddOne(int&y);
都一样!
这篇关于其中&符号“&"通过引用传递参数时可以放置吗?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!