一个类具有重载运算符 new
和 delete
.new
是公开的,delete
是私有的.
A class has overloaded operators new
and delete
. new
is public, delete
is private.
在构造此类的实例时,出现以下错误:
When constructing an instance of this class, I get the following error:
pFoo = new Foo(bar)
example.cpp(1): 错误 C2248: 'Foo:operator delete': 无法访问类 'Foo' 中声明的私有成员
但是这里没有调用delete
,那么编译器的扭曲思想是怎么回事?:)
But there's no call to delete
here, so what is going on in the twisted mind of the compiler? :)
CreateInstance
函数的情况下解决问题?CreateInstance
function?当你执行 new Foo()
时,会发生两件事:首先调用 operator new
来分配内存,然后调用 Foo
的构造函数.如果该构造函数抛出异常,因为您无法访问已分配的内存,C++ 运行时将通过将其传递给适当的 operator delete
来处理它.这就是为什么你总是必须为你编写的每个 operator new
实现一个匹配的 operator delete
并且这就是它需要可访问的原因.
When you do new Foo()
then two things happen: First operator new
is invoked to allocate memory, then a constructor for Foo
is called. If that constructor throws, since you cannot access the memory already allocated, the C++ runtime will take care of it by passing it to the appropriate operator delete
. That's why you always must implement a matching operator delete
for every operator new
you write and that's why it needs to be accessible.
作为一种出路,您可以将它们都设为私有并从公共成员函数(如 create()
)调用 operator new
.
As a way out you could make both of them private and invoke operator new
from a public member function (like create()
).
这篇关于公共运营商新建,私有运营商删除:获取C2248“无法访问私有成员"当使用新的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!