• <small id='yMGDJ'></small><noframes id='yMGDJ'>

    1. <legend id='yMGDJ'><style id='yMGDJ'><dir id='yMGDJ'><q id='yMGDJ'></q></dir></style></legend>
      <i id='yMGDJ'><tr id='yMGDJ'><dt id='yMGDJ'><q id='yMGDJ'><span id='yMGDJ'><b id='yMGDJ'><form id='yMGDJ'><ins id='yMGDJ'></ins><ul id='yMGDJ'></ul><sub id='yMGDJ'></sub></form><legend id='yMGDJ'></legend><bdo id='yMGDJ'><pre id='yMGDJ'><center id='yMGDJ'></center></pre></bdo></b><th id='yMGDJ'></th></span></q></dt></tr></i><div id='yMGDJ'><tfoot id='yMGDJ'></tfoot><dl id='yMGDJ'><fieldset id='yMGDJ'></fieldset></dl></div>

      <tfoot id='yMGDJ'></tfoot>
      • <bdo id='yMGDJ'></bdo><ul id='yMGDJ'></ul>

        使用唯一的动态变量名(不是变量值!)

        时间:2023-09-27
        <legend id='SaOdC'><style id='SaOdC'><dir id='SaOdC'><q id='SaOdC'></q></dir></style></legend>

                <tfoot id='SaOdC'></tfoot>
                <i id='SaOdC'><tr id='SaOdC'><dt id='SaOdC'><q id='SaOdC'><span id='SaOdC'><b id='SaOdC'><form id='SaOdC'><ins id='SaOdC'></ins><ul id='SaOdC'></ul><sub id='SaOdC'></sub></form><legend id='SaOdC'></legend><bdo id='SaOdC'><pre id='SaOdC'><center id='SaOdC'></center></pre></bdo></b><th id='SaOdC'></th></span></q></dt></tr></i><div id='SaOdC'><tfoot id='SaOdC'></tfoot><dl id='SaOdC'><fieldset id='SaOdC'></fieldset></dl></div>

                <small id='SaOdC'></small><noframes id='SaOdC'>

                  <tbody id='SaOdC'></tbody>
                  <bdo id='SaOdC'></bdo><ul id='SaOdC'></ul>

                  本文介绍了使用唯一的动态变量名(不是变量值!)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                  问题描述

                  好吧,这比其他任何事情都重要.

                  Ok so, this is more a sanity check than anything else.

                  假设我们有一个名为 lua_State 的结构,现在我需要创建不确定数量的唯一 lua_State.为了确保我不会两次使用相同的变量名,我需要在每次创建新状态时使用某种方法来获取唯一变量.

                  Lets asume we have a struct called lua_State, now I need to create a uncertain amount of unique lua_State's. To make sure I don't use the same variable name twice I would need to have some sort of way to get an unique variable every time i make a new state.

                  但是,只有一种方法(我认为?)来创建新状态,如下所示:

                  However there is only one way (I think?) to create a new state, and that is as follows:

                  lua_State *S = lewL_newstate();
                  

                  现在我需要某种方法来动态地将S"更改为..无论如何.

                  Now I would need some way to dynamically change that "S" to.. whatever.

                  例如:如果我有 4 个 lua 文件,并且我想将每个文件加载到它们自己的 lua_State 中,我会调用: lua_State *A = lewL_newstate();首先,lua_State *B = lewL_newstate();第二个,依此类推.请记住,lua 文件的数量各不相同,因此创建固定数量的状态可能不会顺利.

                  For example: If I had 4 lua files, and I wanted to load each into their own lua_State, I would call: lua_State *A = lewL_newstate(); for the first, lua_State *B = lewL_newstate(); for the second, and so on. Keep in mind the number of lua files varies so creating a fixed number of states probably won't go over well.

                  我该怎么做?

                  澄清:

                  .h

                  struct lua_State
                  

                  .cpp

                  createNewState(Lua_State* something){
                   lua_State* something = luaL_newstate();
                  }
                  

                  我想过创建一个

                  std::map<int, lua_State*> luaMap;
                  

                  但是我仍然会遇到为每个 int-index 实际生成变量名(因为缺少更好的词)的问题.

                  but then I would still have the problem of actually generating (for lack of better words) a variable name for every int-index.

                  那么,我是不是喝了太多咖啡,是否有一个显而易见的简单解决方案来解决我想要做的事情,或者我应该停止编码直到疯狂结束?

                  So, have I been drinking too much coffee and is there a glaringly obvious simply solution to what I am trying to do, or should I just stop coding untill the crazy blows over?

                  提前致谢.

                  推荐答案

                  使用 std::vector 来存储创建的状态并生成顺序标识符(即数组索引).除非我遗漏了什么,否则您的要求过于复杂.

                  Use a std::vector to both store the created states and generate sequential identifiers (i.e. array indices). Unless I'm missing something, then you are grossly over-complicating your requirements.

                  std::vector<lua_State *> stateList;
                  
                  // create a new Lua state and return it's ID number
                  int newLuaState()
                  {
                      stateList.push_back(luaL_newstate());
                      return stateList.size() - 1;
                  }
                  
                  // retrieve a Lua state by its ID number
                  lua_State * getLuaState(int id)
                  {
                      assert(0 <= id && stateList.size() > id);
                      return stateList[id];
                  }
                  

                  这篇关于使用唯一的动态变量名(不是变量值!)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

                  上一篇:在 C++ 中嵌入 Lua 下一篇:如何使用 C API 创建嵌套的 Lua 表

                  相关文章

                      <bdo id='T0kLv'></bdo><ul id='T0kLv'></ul>

                  1. <legend id='T0kLv'><style id='T0kLv'><dir id='T0kLv'><q id='T0kLv'></q></dir></style></legend>

                    <small id='T0kLv'></small><noframes id='T0kLv'>

                    <tfoot id='T0kLv'></tfoot>
                      <i id='T0kLv'><tr id='T0kLv'><dt id='T0kLv'><q id='T0kLv'><span id='T0kLv'><b id='T0kLv'><form id='T0kLv'><ins id='T0kLv'></ins><ul id='T0kLv'></ul><sub id='T0kLv'></sub></form><legend id='T0kLv'></legend><bdo id='T0kLv'><pre id='T0kLv'><center id='T0kLv'></center></pre></bdo></b><th id='T0kLv'></th></span></q></dt></tr></i><div id='T0kLv'><tfoot id='T0kLv'></tfoot><dl id='T0kLv'><fieldset id='T0kLv'></fieldset></dl></div>