我有文件路径.我怎样才能得到它的 MD5 哈希值?
I've the file path. How can I get the MD5 hash of it?
这是 md5sum
命令的直接实现,它计算并显示在命令行上指定的文件的 MD5.它需要链接到 OpenSSL 库 (gcc md5.c -o md5 -lssl
) 才能工作.它是纯 C 语言,但您应该能够轻松地将其调整到您的 C++ 应用程序中.
Here's a straight forward implementation of the md5sum
command that computes and displays the MD5 of the file specified on the command-line. It needs to be linked against the OpenSSL library (gcc md5.c -o md5 -lssl
) to work. It's pure C, but you should be able to adapt it to your C++ application easily enough.
#include <sys/types.h>
#include <sys/stat.h>
#include <sys/mman.h>
#include <fcntl.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <openssl/md5.h>
unsigned char result[MD5_DIGEST_LENGTH];
// Print the MD5 sum as hex-digits.
void print_md5_sum(unsigned char* md) {
int i;
for(i=0; i <MD5_DIGEST_LENGTH; i++) {
printf("%02x",md[i]);
}
}
// Get the size of the file by its file descriptor
unsigned long get_size_by_fd(int fd) {
struct stat statbuf;
if(fstat(fd, &statbuf) < 0) exit(-1);
return statbuf.st_size;
}
int main(int argc, char *argv[]) {
int file_descript;
unsigned long file_size;
char* file_buffer;
if(argc != 2) {
printf("Must specify the file
");
exit(-1);
}
printf("using file: %s
", argv[1]);
file_descript = open(argv[1], O_RDONLY);
if(file_descript < 0) exit(-1);
file_size = get_size_by_fd(file_descript);
printf("file size: %lu
", file_size);
file_buffer = mmap(0, file_size, PROT_READ, MAP_SHARED, file_descript, 0);
MD5((unsigned char*) file_buffer, file_size, result);
munmap(file_buffer, file_size);
print_md5_sum(result);
printf(" %s
", argv[1]);
return 0;
}
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