这可能是一个基本问题,但我现在看不到自己的回复.
This is maybe a basic question, but I cannot see the response by myself right now.
考虑以下代码:
template<bool b>
struct T {
static constexpr int value = (b ? 42 : 0);
};
template<bool b>
struct U {
enum { value = (b ? 42 : 0) };
};
int main() {
static_assert(T<true>::value == 42, "!");
static_assert(T<false>::value == 0, "!");
static_assert(U<true>::value == 42, "!");
static_assert(U<false>::value == 0, "!");
}
我习惯于使用像 T
这样的结构,但我不止一次看到像 U
这样的结构用于相同的目的(主要是特征定义).
I'm used to using structs like T
, but more than once I've seen structs like U
used for the same purpose (mostly traits definition).
据我所知,它们都是在编译时解决的,它们解决了几乎相同的问题,但在我看来 T
比 U
更具可读性代码>(好吧,我知道,我的个人意见).
As far as I can see, they are both resolved at compile time and they solve almost the same problem, but it seems to me that T
is far more readable than U
(well, I know, my personal opinion).
我的问题很简单:有什么技术原因可以证明一种解决方案比另一种更好吗?
更重要的是,是否有任何一种情况不是可行的解决方案?
My question is pretty simple: is there any technical reason for which one solution is better than the other one?
Even more, is there any case for which one of them is not a viable solution?
请注意,以下答案不适用于 C++ 17 及更高版本.
这样使用时,积分常数不会有明显差异.
There will be no noticeable difference for integral constants when used like this.
然而,enum
实际上更好,因为它是一个真正的命名常量.constexpr
整数常量是一个对象,例如可以被 ODR 使用 - 这会导致链接错误.
However, enum
is actually better, because it is a true named constant. constexpr
integral constant is an object which can be, for example, ODR-used - and that would result in linking errors.
#include <iostream>
struct T {
static constexpr int i = 42;
enum : int {x = 42};
};
void check(const int& z) {
std::cout << "Check: " << z << "
";
}
int main() {
// check(T::i); // Uncommenting this will lead to link error
check(T::x);
}
当check(T::i)
被取消注释时,程序无法链接:
When check(T::i)
is uncommented, the program can not be linked:
/tmp/ccZoETx7.o
:在函数`main
'中:ccc.cpp
:(.text+0x45
): 未定义引用 `T::i
' collect2
:错误:ld
返回 1
退出状态
/tmp/ccZoETx7.o
: In function `main
':ccc.cpp
:(.text+0x45
): undefined reference to `T::i
'collect2
: error:ld
returned1
exit status
然而,真正的 enum
总是有效的.
However, the true enum
always works.
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