我正在尝试按照示例解析提升精神 (2.5.2) 的示例.我的代码如下
I'm trying to parse an example of boost spirit (2.5.2) following the example. My code is the following
#include <boostspirithomeqi.hpp>
#include <iostream>
#include <string>
#include <utility>
int main()
{
// Parsing two numbers
std::string input("1.0 2.0");
std::pair<double, double> p;
boost::spirit::qi::phrase_parse(
input.begin(),
input.end(),
boost::spirit::qi::double_ >> boost::spirit::qi::double_ , // Parse grammar
boost::spirit::qi::space,
p
);
return 0;
}
它几乎等于找到的例子 此处,但是当我使用 Visual Studio 2010(32 位,调试)编译它时,出现以下错误:
It's almost equal to the example found here, but when I compile it with Visual studio 2010 (32 bit, debug) I obtain the following error:
error C2440: 'static_cast': unable to convert from 'const double' to 'std::pair<_Ty1,_Ty2>'
(错误可能略有不同,我是从意大利语翻译过来的)
(the error can be slighty different, I've translated it from italian)
我做错了什么,我怎样才能成功编译这个例子?
What I'm doing wrong and how can I compile successfully the example?
预先感谢您的回复.
您缺少一个包含:
#include <boost/fusion/adapted/std_pair.hpp>
它定义了属性分配规则,使 Fusion 序列 (vector2<>) 可分配给 std::pair.
It defines the attribute assignment rules to make Fusion sequences (vector2<>) assignable to std::pair.
查看实时代码:liveworkspace.org
See the code live: liveworkspace.org
#include <boost/spirit/include/qi.hpp>
#include <boost/fusion/adapted/std_pair.hpp>
#include <iostream>
#include <string>
#include <utility>
int main()
{
// Parsing two numbers
std::string input("1.2 3.4");
std::pair<double, double> p;
namespace qi = boost::spirit::qi;
qi::phrase_parse(
input.begin(),
input.end(),
qi::double_ >> qi::double_ , // Parse grammar
qi::space, p);
std::cout << "Lo: " << p.first << "
"
<< "Behold: " << p.second << "
";
}
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