void weight_data::rev_seq(string &seq){
//TODO
std::reverse(seq.begin(), seq.end());
}
在这个C++的方法中,我认为这个方法没有返回任何东西,所以前缀是void
,::
告诉了weight_data<之间的关系/code> 和
rev_seq(string &seq)
?谢谢!
In this C++ method, I think this method does not return anything, so the prefix is void
, what does ::
tell the relationships between weight_data
and rev_seq(string &seq)
? Thanks!
void
是返回类型.::
是作用域解析操作符,表示rev_seq
在weight_data
的作用域内.weight_data
可以是命名空间或类(根据您提供的内容,无法确定是哪个).
void
is the return type. ::
is the scope resolution operator, so it means rev_seq
is inside the scope of weight_data
. weight_data
could be either a namespace or a class (based on what you've given, it's not possible to say which).
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